4c^3-16c^2=128c

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Solution for 4c^3-16c^2=128c equation:


Simplifying
4c3 + -16c2 = 128c

Reorder the terms:
-16c2 + 4c3 = 128c

Solving
-16c2 + 4c3 = 128c

Solving for variable 'c'.

Reorder the terms:
-128c + -16c2 + 4c3 = 128c + -128c

Combine like terms: 128c + -128c = 0
-128c + -16c2 + 4c3 = 0

Factor out the Greatest Common Factor (GCF), '4c'.
4c(-32 + -4c + c2) = 0

Factor a trinomial.
4c((-4 + -1c)(8 + -1c)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(-4 + -1c)' equal to zero and attempt to solve: Simplifying -4 + -1c = 0 Solving -4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1c = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1c = 0 + 4 -1c = 0 + 4 Combine like terms: 0 + 4 = 4 -1c = 4 Divide each side by '-1'. c = -4 Simplifying c = -4

Subproblem 3

Set the factor '(8 + -1c)' equal to zero and attempt to solve: Simplifying 8 + -1c = 0 Solving 8 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1c = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1c = 0 + -8 -1c = 0 + -8 Combine like terms: 0 + -8 = -8 -1c = -8 Divide each side by '-1'. c = 8 Simplifying c = 8

Solution

c = {0, -4, 8}

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